Friday, January 09, 2009


A couple of months ago, blogging friend Connie from Connie's Thoughts awarded me the BFF Gold Card....BLOGGING FRIENDS FOREVER! Isn't it so cute? The idea behind this award is that you send it to three bloggers who have regularly commented on your blog and also to one new blogging friend. The 3 people that I have chosen to pass this award on to are bloggers that have visited and commented on my blog in the beginning of my blogging days.
1) Always the encourager to both Shane and I, Jen of Pen of Jen
2) Always reminding me of God's awesome power, Susan of Penless Writer
3) Always treating me like a sister, (cuz we are sisters!) Rita, of The Jungle Hut
4) My new and witty blogging friend, NINA of Portugal Bound
Connie, I'm so thankful you thought of me for this award. I'm so sorry it has taken so long to follow award it to these other lovely bloggers! I have had the award displayed on my side margin though since first receiving it!


Betty said...

Congrats on receiving this award! I agree with your selection. I regularly read Susan and Rita´s blog too and they deserve it!


Good job, Pam. I love all those who you gave the award to. They are very special to me also. Thank you. connie

Kristi said...

What a cute idea!


Anonymous said...

Congrats! Connie is very thoughtful isn't she?

Soul Skittles said...

Sorry I haven't commented in a while!
Kudos. :D It's so shiny.

Nina in Portugal said...

awww..Pam...I'm you new, witty blogging sweet.

Thank you for the award and as soon as I'm finished doing the Hubby tag that you did in your previous post, I'll follow through with my end of the deal.

I thought that hubby tag was too cute and my husband deserves a little recognition. (He's been washing dishes lately...shhhhh....)

Thanks again...and soon I'll follow through....promise!

Bom Fim Semana!

justabeachkat said...

Congrats on the award.


lizzykristine @ Uplifted Eyes said...

Congratulations! And thanks for delurking with your blog address. ;)

Shane Rios said...

Also Great Post Mom.=)